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OpenStudy (anonymous):

Write an equation of the line given the following conditions: perpendicular to the x-axis & passes through the point (-5, 2). Please Help.

OpenStudy (anonymous):

Hi, cc104567

OpenStudy (anonymous):

Do you remember the relation between the slopes of two perpendicular lines?

OpenStudy (anonymous):

the slopes are the oppodite values of each other

OpenStudy (anonymous):

Mmm that is almost correct. Actually the product of the slopes of two perpendicular lines is equal to -1 \[m1⋅m2=−1\]

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

Well x axis is an horizontal line.

OpenStudy (anonymous):

what kind of line is perpendicular to an horizontal line?

OpenStudy (anonymous):

a vertical line

OpenStudy (anonymous):

Yeah!. What is the equation of a vertical line?

OpenStudy (anonymous):

y=0

OpenStudy (anonymous):

No, y=0, is horizontal line. All the points like these: (1,0),(2,0),(3,0) lie on that line.

OpenStudy (anonymous):

If you have a vertical lines all of its points looks like these (5,0),(5,1),(5,2),(5,10), etc.

OpenStudy (anonymous):

A vertical line that passes trought the point (2,2) is x=2

OpenStudy (anonymous):

k, so the answer is to negate the x-value

OpenStudy (anonymous):

No, you know that is a vertical line, so you know it's something like x = somenumber

OpenStudy (anonymous):

Actually the x-value of your point is telling you what is the equation.

OpenStudy (anonymous):

What is the x-value of the point (5,-2)?

OpenStudy (anonymous):

x=-5 ??

OpenStudy (anonymous):

thanks I understand now x=5 is the equation right?

OpenStudy (anonymous):

|dw:1325640836730:dw|

OpenStudy (anonymous):

Yes, that is the equation, did you understand why?

OpenStudy (anonymous):

you negated both the x and y values to make it perpendicular and the x-axis is supposed to make the equation

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

I didn't do that.

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