Question

please help i give out medals :)
write an equation for a line perpendicular to this: y-6 = 2(x-4)

Answer 1

y-6 = 2(x-4)
y=2x-8+6
y=2x-2
let x=0=>y=-2
from the equation we could say the slope is 2
the slope of the required line is -1/2
so the equation is y=-1/2(X) +c
substituting the points to find c,,,,,
we get c = -2
so , the equation is y=-1/2(X)+ c

Answer 2

y=2x-8+6
y=2x+2--- in slope form( y=mxb).
to write a perpendicular eq. change the sign and and the reciprocal of the slope (mx) so, is y=- 1/2x+2 the answer

Answer 3

oh and before what i did with the original equations y-6 = 2(x-4)
is i think is in y-intercept form, i dont remember really its been years since i haven't seen this,
you solve to get y=mx+b, m being the slope and b being the y-intercept in the graph. so, solve the parenthesis first, your left with y-6=2x-8.
then add 6 to both sides, so it cancels out in the left and your left with y=2x-2. and then u do what i told you in the last post... hope it helps :)