Question

the area of a rectangular field is x^2-x-72 m^2. the length of the field is x+8 m(meters). what is the width of the field in meters?

Answer 1

You know that area=(length)(width)
So you have:
\[x^2-x-72=(x+8)*w\]
Solve for w.

Answer 2

wow i appreciate it, thank you for your quick answer

Answer 3

so W would be?

Answer 4

the length would be 8?

Answer 5

Well the left side factors to:
\[(x-9)(x+8)=(x+8)w \implies w=(x-9)\]

Answer 6

i find trouble resolving this clearly arg

Answer 7

So w would be x-9 meters

Answer 8

yes but the x would be?

Answer 9

or there is no clear answer because it doesnt tell right ?

Answer 10

You can't solve it from the information given. You know l in terms of x, you know w in terms of x, and you know area in terms of x, you can't solve x explicitly the way I see it.

Answer 11

so there is no term since it is not given we finish at W=x-9
thank you very much for your patience

Answer 12

No problem