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OpenStudy (anonymous):
what is the inverse relation for 2x+3y=10
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OpenStudy (anonymous):
First solve for y:
3y = -2x +10
or
y = (-2/3)x + 10/3
Do you know the next step?
OpenStudy (anonymous):
i have to resolve the x and y ?
OpenStudy (mertsj):
2y+3x=10
OpenStudy (anonymous):
but the steps?
OpenStudy (anonymous):
i got what meverett is saying, so what do i do next ?
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OpenStudy (anonymous):
2x+3y=10
Subtract 2x from both sides
3y = -2x +10
Divide by 2
y = (-2/3)x + 10
OpenStudy (anonymous):
so that would be its inverse?
OpenStudy (anonymous):
no ....
First solve for y:
3y = -2x +10
or
y = (-2/3)x + 10/3
Do you know the next step?
OpenStudy (anonymous):
no
OpenStudy (anonymous):
i prefer the 3y=-2x+10 since it has no fraction
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OpenStudy (anonymous):
okay, take the 3y=-2x+10
and switch the x and y
3X = -2Y + 10
and solve for this new Y .... mom is calling ..... gotta go ... sorry ...
OpenStudy (anonymous):
ok thank you very much
OpenStudy (anonymous):
so the final result would be ?
OpenStudy (mertsj):
Just interchange the x and y and solve for y.|dw:1325725560297:dw|
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