Question

See attachment.

Answer 1

Do you know the quadratic formula?
\[\Large \frac{{ - b \pm \sqrt {{b^2} - 4ac} }}{{2a}}\]
To the specified polynomial, where a = 1, b = -3, and c = 7.

Answer 2

For the record:\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]where\[ax^2+bx+c=0\]is your polynomial.

Answer 3

FSM and I seem to both know it by heart. What does that tell you, joyce153? It must be important!

Answer 4

Haha indeed. It is very nifty to memorise!

Answer 5

lol ok. So whats the answer?

Answer 6

Try and work it out :-P Substitute the appropriate values in the quadratic formula (the formula above across and I posted) and see what you can come up with.

Answer 7

Are you familiar with complex numbers?

Answer 8

I got \[x=\left(\begin{matrix}3+i \sqrt{19} \\ 2\end{matrix}\right),\left(\begin{matrix}3-i \sqrt{19} \\ 2\end{matrix}\right)\]on mathway