Question

Can someone show me how to find the Value of "a" in this rather simple arithmetic means problem? Grade 11...

Totally blanked out as a result of the break :P

Answer 1

Determine the missing terms in the arithmetic sequence which has

T1 = -a/2
T6 = 2a

Answer 2

I deleted the old one by accident my bad...

Answer 3

for a I got -a/2
d I got : a/2

Answer 4

not sure if i am correct..

Answer 5

t1 = -a/2
t2=-a/2+d
t3=-a/2+2d
t4=-a/2+3d
t5=-a/2+4d
t6=-a/2+5d = 2a

is what im thinking of

Answer 6

Yup amistre64 that's what I based it on as well

Answer 7

The elements of an arithmetic sequence are separated by a common difference. If you can find that difference, then you can calculate the value of any element in the sequence.

The first element of the sequence is \(\frac{-a}{2}\) and for any arithmetiv sequence with common difference d, \[a_n = a_{n-1} + d(n-1)\]

Answer 8

then I did

t6 = a + 5d

so 2a - ( - a/2) = 5d
d = a/2

Answer 9

right

Answer 10

5d = 2a + a/2
= (4a+a)/2
= 5a/2

d = 5a/2.5

d = a/2

i agree so far lol

Answer 11

i did a little mistake in my rule though, instead of \(a_{n-1}\)it should be \(a_1\)

Answer 12

True

Answer 13

i think your answer is right

Answer 14

It's right so far I guess, the final answers given in my book are:

0, 0.75, 1.1 , 1.45 as the missing terms

Answer 15

Oh well thanks for helping ...

Answer 16

I'll think a little more and see if I get anywhere:P

Answer 17

GOT IT :D