please help with the attached line proof
There is no way BD can be parallel to AD However, If the proposition is that BC is parallel to AD then: <BEC is congruent with <DEA AE is congruent with EC DE is congruent with EB By SAS triangles BEC and DEA are congruent Since the triangles are congruent <EAD is congruent to <ECB and considering AC as transversal BC is parallel to AC since the alternate interior angles are congruent
Those are the statements but what are the reasons can you fill the table out on the attached file and reattach it when you're done Please?
What's the theorem that says two lines intersecting create congruent opposite angles? (that's the first) 2nd and 3rd - by definition of bisection SAS is the reason they are congruent Congruence it the reason the angles are congruent the last is either Euclid's parallel postulate or parallel transveral theorem depending on what you are being taught
thanks
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