Question

put this: (x-1)^2=12(y-1)
in this form: y=a(x-h)^2+k^2

Answer 1

\[(x-1)^2=12(y-1)\]
\[(x-1)^2=12y-12)\]
\[12y = (x-1)^2 +12\]
\[y = \frac{(x-1)^2 +12}{12}\]
\[y = \frac{(x-1)^2}{12}+ \frac{12}{12}\]

Answer 2

\[y = \frac{1}{12} (x-1)^2 + 1\]