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In Problem Set 1, Part 1C- Slope and Derivative, Question 4a), how does a sketcher know where the peak of the left part of the graph is? Can you tell without differentiating?
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Now that I looked again at the question... \[x <-2, \] then the function is always negative... but the y-intercept is 0, so it can't go higher than that. Is there any other way to figure it out where the peak is?
Hi kablooey, eyeballing the peak can be very misleading. It is better to differentiate, however, some people have shown a knack for visualizing peaks and locations of lines, peaks and slopes.
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