Question

could you please help, make c the subject of A= 1/2(b+c)h

Answer 1

\[\Large \begin{array}{l}
A = \frac{1}{2}(b + c)h\\
c = \frac{{2A}}{h} - b
\end{array}\]

Answer 2

my friend thinks the answer is c=2A-bh/h

Answer 3

Sadly, your friend is incorrect!

Answer 4

\[\Large \begin{array}{l}
A = \frac{1}{2}(b + c)h\\
(b + c) = \frac{A}{{\frac{1}{2}h}}\\
c = \frac{{2A}}{h} - b
\end{array}\]
Let's assign some arbitrary values and test it:
b = 2, c = 3, h = 4.
A = (1/2)(2+3)4 = 10
c = ((2*10)/4) - 2 = (20/4) - 2 = 5 - 2 = 3. Seems legit.

Answer 5

easy:


1. mutiply both sides by 2,
2. divide boht sides by h
3. subtract b from both sides

done!

Answer 6

could someone please guide me through each step