Mathematics
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OpenStudy (anonymous):
Can someone teach me systems of equations?
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OpenStudy (anonymous):
a linear system is simply a set of linear equations.
OpenStudy (anonymous):
Ok, but can you give me an example so i can try?
OpenStudy (anonymous):
here's an easy one:
2x + y = 3
x + y = 1
OpenStudy (anonymous):
2x + y = 3
+ x + y = 1
Is this the right first step?
OpenStudy (anonymous):
you can do 3 different things to solve a linear system:
1. graph the equations, and find where they intersect.
2. substitution
3. elimination.
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OpenStudy (anonymous):
Im gonna do elimination then substitution
OpenStudy (anonymous):
No wait
OpenStudy (anonymous):
I cant do elimination on this one
OpenStudy (anonymous):
2x + y = 3
+ x + -y = 1-2y
3x=4-2y
OpenStudy (anonymous):
That cant be right
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OpenStudy (anonymous):
you can; in fact elimination would be the easy way out of this one
OpenStudy (anonymous):
WAIT
OpenStudy (anonymous):
Can i divide the equations?
OpenStudy (anonymous):
if you subtract equation 2 from equation 1: you get
x = 2
x + y = 1
next step is to subtract the new equation 1 from equation 2
OpenStudy (anonymous):
y=1?
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OpenStudy (anonymous):
you can't really divide the equations
OpenStudy (anonymous):
Ok, i see why now
OpenStudy (anonymous):
Give me another one so i can try, i think i see the pattern
OpenStudy (anonymous):
2x + y = 5
x + y = 3
OpenStudy (anonymous):
2x + y = 5 - x + y = 3 = x=2? The y's cancel out right?
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OpenStudy (anonymous):
Now i can substitute to get y
OpenStudy (anonymous):
right
OpenStudy (anonymous):
2 + y = 3
y=1
OpenStudy (anonymous):
I can cross check this with the other equation
OpenStudy (anonymous):
4 + 1 = 5
2 + 1 = 3