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Mathematics 20 Online
OpenStudy (anonymous):

Can someone teach me systems of equations?

OpenStudy (anonymous):

a linear system is simply a set of linear equations.

OpenStudy (anonymous):

Ok, but can you give me an example so i can try?

OpenStudy (anonymous):

here's an easy one: 2x + y = 3 x + y = 1

OpenStudy (anonymous):

2x + y = 3 + x + y = 1 Is this the right first step?

OpenStudy (anonymous):

you can do 3 different things to solve a linear system: 1. graph the equations, and find where they intersect. 2. substitution 3. elimination.

OpenStudy (anonymous):

Im gonna do elimination then substitution

OpenStudy (anonymous):

No wait

OpenStudy (anonymous):

I cant do elimination on this one

OpenStudy (anonymous):

2x + y = 3 + x + -y = 1-2y 3x=4-2y

OpenStudy (anonymous):

That cant be right

OpenStudy (anonymous):

you can; in fact elimination would be the easy way out of this one

OpenStudy (anonymous):

WAIT

OpenStudy (anonymous):

Can i divide the equations?

OpenStudy (anonymous):

if you subtract equation 2 from equation 1: you get x = 2 x + y = 1 next step is to subtract the new equation 1 from equation 2

OpenStudy (anonymous):

y=1?

OpenStudy (anonymous):

you can't really divide the equations

OpenStudy (anonymous):

Ok, i see why now

OpenStudy (anonymous):

Give me another one so i can try, i think i see the pattern

OpenStudy (anonymous):

2x + y = 5 x + y = 3

OpenStudy (anonymous):

2x + y = 5 - x + y = 3 = x=2? The y's cancel out right?

OpenStudy (anonymous):

Now i can substitute to get y

OpenStudy (anonymous):

right

OpenStudy (anonymous):

2 + y = 3 y=1

OpenStudy (anonymous):

I can cross check this with the other equation

OpenStudy (anonymous):

4 + 1 = 5 2 + 1 = 3

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