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Mathematics 22 Online
OpenStudy (anonymous):

simplify completely 5x^2+9x-2/x^2+12x+20*x^2+17x+70/15x-3

OpenStudy (anonymous):

Please help, i dont know how

OpenStudy (anonymous):

i dont get it...

OpenStudy (anonymous):

the whole thing, can you walk me threw it?

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

Can you tell me if the expression you are trying to simplify is a series of single terms? or does it have a numerator or denominator with multiple terms?

OpenStudy (anonymous):

ohh okay, the answers are x+7/3(x+10), x+2/3(x+10), x+10/3 and x+7/3

OpenStudy (anonymous):

one of those is the answer

OpenStudy (anonymous):

PLEASE HELP

OpenStudy (anonymous):

Ok, I think this is your problem ( which we will solve) Parenthesis and grouping matters (5x^2+9x-2)/(x^2+12x+20) * (x^2+17x+70)/(15x-3)

OpenStudy (anonymous):

So, for your first fraction. Factor numerator and denominator and you get \[[(5x-1)(x+2)]/[(x+10)(x+2)]\] Now, see the (x+2) can cancel?

OpenStudy (anonymous):

Oh okay im sorry i didnt know because its not written how i typed it like because my computer wouldnt let me

OpenStudy (anonymous):

So we are left with (5x-1)/(x+10) For the second fraction, we again factor and get \[[(x+10)(x+7)]/[3*(5x-1)]\]

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

Multiplying across, our new numerator is (5x-1)(x+10)(x+7) And our new denominator is (x+10)(5x-1)*3 And now we can cancel the (5x-1) and the (x+10) and we are left with (x+7)/3

OpenStudy (anonymous):

It's ok, does this help?

OpenStudy (anonymous):

yes thank you so much!!! do you think you can help me with one more question?

OpenStudy (anonymous):

Is it the other one you have posted? I think it'll be a similar grouping confusion... meet you over there

OpenStudy (anonymous):

haha yeah

OpenStudy (anonymous):

no x^2+x-12 i mean that

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