Determine the number of solutions for the quadratic function f(x) = x2 - 6x + 9.
(Points : 2)

No real solutions

1 solution (double root)

2 distinct real solutions

Question

Determine the number of solutions for the quadratic function f(x) = x2 - 6x + 9.
(Points : 2)
      
No real solutions

1 solution (double root)

2 distinct real solutions

mertsj · Answer

Calculate the discriminant.  Do you know what that is?

anonymous · Answer

no

anonymous · Answer

1 solution   discriminant = 0
x=3 is solution

mertsj · Answer

It is the part of the quadratic formula that is under the radical.  b^2-4ac

mertsj · Answer

Way to go jadest

anonymous · Answer

thanks guys!

mertsj · Answer

yw

across · Answer

I believe this kind of questions tend to confuse students down the road; every polynomial of the form $a_nx^n+a_{n-1}x^{n-1}+...+a_1x+a_0=0$ has $n$ solutions in $\mathbb{C}$. It seems teachers nowadays refer to "solutions" as those who can only be found in $\mathbb{R}$. Someone correct me if I'm wrong.