Question

how would i graph 1x^2+7x+36 = 0

Answer 1

You try to find the value of f(x), for x=-1, 0, 1, 2, 3 etc

Answer 2

If you find the value of f(x) for x=-1, 0, 1 ... it should be enough to give you a clue of how the graph look like.

Answer 3

Yeah but if I have graphing technology is it in the right form to do that for me

Answer 4

I don't recall the details, but given the roots are not real, there has to be a different approach I think.

Answer 5

8 or (-7 + i*sqrt(95))/2 or (-7 – i*sqrt (95))/2

Answer 6

Those are the roots (thanks again for the help with that) but I just know I am required to graph it so is it in graphical form or do I need to change it

Answer 7

8 was a root to the previous equation because it had a factor (x-8). This one is a quadratic so just the latter two roots.

Answer 8

i know they want to me to substitute zero for the function notion but i dont get what that means