Find two consecutive even integers such that if 6 more than the first is divided by 6 less than the second, the quotient is 2. how can i set up this problem and figure out the answer?

Question

anonymous · Answer

let numbers be x and x + 2
x+6 
---            = 2
x+2 - 6

x+6 / x - 4  = 2

anonymous · Answer

Let x and y be those two numbers.
y = x+1

Also, x+6/y-6 = 2.

Two equations in two variables. Solve.

anonymous · Answer

Sorry. Even. So, y = x + 2.

anonymous · Answer

solve for x
x + 6 = 2x - 8
x = 14 

so two numbers are 14 and 16

anonymous · Answer

ok cathy ?
you can check if this is correct by going back to the questio

6 more than first = 14+6 = 20
6 less than second = 16-6 = 10

20/10 = 2

anonymous · Answer

need any more help?

anonymous · Answer

no, thanks for your help

anonymous · Answer

yw

anonymous · Answer

plz close question by clicking on good answer