A toddler’s playground has two slides on either side. The slide on the left is situated at a 45° angle to the ground and is 68 centimeters away from the base of the playground. The slide on the right is positioned at a 30° angle to the ground and is 112 centimeters away from the playground’s base. What is the total length of both slides on this playground rounded to the nearest tenth of a centimeter?

Question

anonymous · Answer

This sounds impossible without knowing the length of the slides, at all...?

anonymous · Answer

http://go.flvs.net/courses/1/flvs_57_3641_12624/ppg/respondus/pool_Geom_3641_0404_08/image0034e2eea58.gif

mertsj · Answer

Are you studying the special right triangles?

mertsj · Answer

It is very hard to help someone who will not respond.

anonymous · Answer

yes i am sorry

anonymous · Answer

Oh I see what it's saying... I thought the question read like "The playground was 68cm off of the floor of the playground." Use a sin or cos function; cannot remember their formulas, sorry.

mertsj · Answer

The red triangle is a 45-45-90 .  In this triangle, the hypotenuse (which is the length of the slide) is the leg multiplied by sqrt2  so the red slide is 68sqrt centimeters

anonymous · Answer

ooooh so the answer is 68 or don't i have to add something? i'm so confused

mertsj · Answer

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