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solve for x: √2x=3=x
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thers must be a mistake in yur question jake - theres two '=' signs
oh sorry its √2x+3 =x
\[\sqrt{2x} or \sqrt2 x\] ?
or\[\sqrt{2x+3}\] ?
\[\sqrt{2x+3}=x\]
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Cool. Square both sides to get: 2x + 3 = x^2 x^2 - 2x -3 = 0 (x+1)(x-3) = 0 x = -1 or x=3
square both sides
Now, test the answers. It can't be -1 So answer is 3.
^No. It can't be -1 because: sqrt(1) is not equal to -1. Always plug in the values and test it.
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