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change e^2x=75 to logarithmic form
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ln(75)/2 = x
\[e ^{2x}=75\] \[2x \ln e=\ln 75\] \[2x=\ln 75 \therefore x=(\ln 75)/2\]
x=2.159
use the properties of logarithms to write the expression, log \[\sqrt[5]{3y/x}\] as a sum, difference, or multiples of logarithms of x, y, or constants. assume that x>0 and y>0
(its log of that square root it wouldnt go together)
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