Question

how do you do these?
I got 2,3, and 4. But I NEED #1
If you could give me all of them that'd be great

Answer 1

http://www.mathbits.com/caching/PC358366.html

Answer 2

so sin x=8/17.
cos x=sqrt(1-xin^2 x)=sqrt(1-64/289)=sqrt(225/289)=-15/17.
as it is given cos x is negative.
so, sec x=1/cos x=-17/15

Answer 3

have u figured it out yet mister?

Answer 4

so the overall answer for #1 is ?

Answer 5

Did you understand the method or not??

Answer 6

not really

Answer 7

Look all u have to do is go back to where that person explained it to you and try harder to under stand it!

Answer 8

bye:D

Answer 9

Do you know sin^2 x + cos ^2 x=1?

Answer 10

yeah

Answer 11

I don't understand what the final answer is for #1. Is it (-17/15) ?

Answer 12

Yeah.

Answer 13

For the rest I have:
2) sin(arctan(1))
3) 5.196152
4) 8.9644
are those right?

Answer 14

#1 \[\cos \Theta\] =-15/17
\[\sec \Theta\] =-17/15

#2 \[\sin(\tan^{-1} (1)=\]
\[\sin 45 =\]
\[\sqrt{2}/2\]
#3 \[6(1/\sqrt{3})-2(-\sqrt{3}/2)\]
\[6(\sqrt{3}/3) + \sqrt{3}\]
\[2\sqrt{3} + \sqrt{3}\]
\[3\sqrt{3}\]
#4 tan 35 = a/10 tan 62 = b/10
a = 0.7002*10 b=1.8807*10
a = 7.002 b = 18.807
Distance between towns is: 18.807-7.002
ans: 11.805

Answer 15

So at the bottom to find the URL i keep doing it but it won't work