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OpenStudy (anonymous):
how would we find the [initial position] for x = t^2 -4t+3
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OpenStudy (anonymous):
oops, -3
OpenStudy (anonymous):
What is x here?
OpenStudy (anonymous):
it doesn't specify
OpenStudy (anonymous):
@ i spy how did you get your answer
OpenStudy (anonymous):
sorry I thought virtus u were responding to the next qn and got confused. the initial position means at t=0, if you plug that into your equation, you get x=3 as the initial position
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OpenStudy (anonymous):
OH I SEEE hahahah thank you @ i spy
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