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The domain of the function f(x)=8x / 5x−1
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pls put in interval notation
u cant have denominator = 0, so 5x-1 not= 0. that gives us x not= 1/5 domain = (-infinity, 1/5)u(1/5,infinity) or domain = (-infinity,infinity)-{1/5}
hey thanks for the help. can you help me with this also The domain of the function f(x)=−15x+12 / x^2−7x+10
factor out the denominator u get (x-5)(x-2) denominator not= 0 so x not=5 and x not=2 if u put into the notation form x = (-infinity,infinity)-{2,5} or x= (-infinty,2) u (2,5) u (5,infinity)
thanks for the help do you mind, i have more questions?
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