Question

can some one help me with the question
y= x^2+5x+6

Answer 1

3*2

Answer 2

okay, but what exactly is the question asking you to do

Answer 3

graph each parabola and give its vertex , axis, x-intercepts , and y-intercept

Answer 4

okay, once we factored it we can set y to be 0 and solve for x, thus obtaining the x-intercepts:

(x+3)(x+2)=0

x+3=0--->x=-3

x+2=0----->x=-2

x-intercepts at (-3,0) and (-2,0)

Answer 5

the x-coordinate of the vertex is giveb by -b/2a

here b=5 and a=1,

thus: -(5)/(2*1)=-5/2, now if we plug this in to our original equation we get:

(-5/2)^2+5(-5/2)+6=-1/4, thus the vertex is located at (-5/2,-1/4)

Answer 6

the y intercept is given by setting x to be zero and solving for y, this :

y=(0)^2+5(0)+5

y=6

thus the y intercept is at (0,6)

Answer 7

thank you and alsoo i have another ques

Answer 8

f(x)=2x^2+8x-8