Just thought I understood exponentials!! An orchestra tunes to a frequency of 440, which sounds the A above middle C. Each octave higher doubles the frequency, and each of the 12 semitones in the octave increases the frequency in the same ration. (a) What's the ratio? (b) Find the frequency of the middle C. (c) Where on the scale is a note with a frequency of 600?
jeez this is annoying
I agree.
oh no scratch that!
Apparently not... It's 1.059
right my mistake put the ratio as "r" then \[r^{12}=2\]
and therefore \[r=\sqrt[12]{2}\] whatever that is
Yes, that makes sense.
It's the answer.
oh good. lost on middle C though. sorry
wow thank god for the internet, check this out http://in.answers.yahoo.com/question/index?qid=20110519083621AAwVvDp
Sorry, my internet left me! I'll check the site. Thanks
It's not very helpful... There you have to differentiate, and with mine, you don't, because that's in the next chapter... and I haven't gone that far... If there's a simpler way, I'd really like to know :)
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