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Solve 2x2 – 8x = –7
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2x^2 - 8x + 7 = 0. Now use quadratic formula.
x=(4 +or- sqrt2)/2
\[\frac{-(-8)\pm\sqrt{(-8)^{2}-4(2)(7)}}{2(2)}= \frac{8\pm\sqrt{8}}{4} \]
mimi how do u put fraction in equation editor....
\frac{}{}
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Latex fraction -> \frac{x}{y}\ = \(\Large \frac{x}{y}\)
\frac{-(-8)\pm\sqrt{(-8)^{2}-4(2)(7)}}{2(2)}= \frac{8\pm\sqrt{8}}{4} (copy and paste that into the equation editor xD)
but those arnt my answers to choose from :(
What are your answers choices?
\[\Large \begin{array}{l} \frac{{8 \pm \sqrt 8 }}{4}\\ = 2.71,1.29 \end{array}\]
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i figured it out its right... can u please help me on my other post i posted
i need help on my other post i posted pleaseeeee
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