Question

Please Help
factorise 9(p+1)^2-4p^2

Answer 1

hi hollywood!

Answer 2

Hey sats

Answer 3

this a tricky one
use
\[a^2-b^2=(a+b)(a-b)\] with
\[a=3(p+1), b=2p\] you want me to walk you through it?

Answer 4

please

Answer 5

\[9(p+1)^2-4p^2\]
\[(3(p+1)+2p)(3(p+1)-2p)\] then we simplify in each set of parentheses

Answer 6

first distribute the "3" inside and get
\[(3p+3+2p)(3p+3-2p)\]

Answer 7

then combine like terms in each parentheses and get your "final answer" of
\[(5p+3)(p+3)\]

Answer 8

Briliant

Answer 9

thank you satellite

Answer 10

(blush) yw