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what's the limit of f(x) = x^2 + 3 as x--> 2
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just substitute x = 2
since we have no indeterminant form at x=2, just do what moneybird said
wait we're just starting to get into these....what do you substitute and why?
if you plug in x=2 then you get an direct answer: the limit if you were to plug in x=2 and got zero in the denominator, or 0/0, or some other indeterminant form, you would have to rearrange the expression to avoid division by zero. fortunately for you we have no such problem, so just plug in the number :)
thanks so much!
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