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Jemurray3
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Sir.
lol
ok so basically like u r given points and u gotta find the equation of the polynomial and plot it
like we jst did previously
But suppose the points were colinnear wld it still work?
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do u have time for this?
Not for a polynomial of degree 2. Three co-linear points would mean that you could draw a straight line through your function that intersects the curve in three places, which is impossible with a quadratic.
oh i didnt even get the question lol
i thought it meant s/t else
|dw:1326445952982:dw| Doesn't work
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oh i see
Suppose four points lie on a common parabola. The method claims you should be able to determine a cubic, but what really happens?
|dw:1326446010363:dw| This could work though.
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