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Mathematics 19 Online
OpenStudy (anonymous):

Could anyone give me a simple word problem that boils down to a differential equation to solve?

OpenStudy (jamesj):

The cup of tea in from of me is currently at 70 C and the air around it is 20 C. The tea cools at a rate proportional to the difference between its temperature and the air temperature. When will the tea be at 50 C and I can drink it?

OpenStudy (anonymous):

i am going to bet that we can do this without any differential equation, yes?

OpenStudy (anonymous):

oh actually no, because i have no idea what the rate of decrease is

OpenStudy (anonymous):

am i confused (probably) or don't we need one additional piece of information? suppose the tea was tar?

OpenStudy (anonymous):

|dw:1326471386752:dw|\[\frac{dT_t}{dt}=-k(T_t-T_a)\]this is what i have so far. brb

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