Find the value of x.
Use SoaCaoToa here. Do you know what do to with that?
No I Dont.
x =root 40
\[\sqrt{40}\]
Ok, so you'll want to use sine, cosine, or tangent here. sin (angle)=opposite/hypotenuse cos (angle)=adjacent/hypotenuse tang (angle)=opposite/adjacent
(sorry, it should be SohCahToa)
I dont understand
\[\sin x = \frac{oppositeside}{hypotenuse}\]\[Sin30= \frac{5}{x}\]\[\frac{1}{2}= \frac{5}{x} \]\[x=5 \times 2 =10\] \(x=10 \)
I disagree with amit's choice to use tan. In this case, since we are solving for the hypotenuse, I would use sine instead
why can u plz explain ?
Even if you take tan you'll get the Answer But its better to take sine as we are calculating opposite side And you've done a mistake in calculation
In this case, we are solving for the hypotenuse and are given the opposite length and an angle measurement. Thus, by the definition, we should use sine here.
Oh yeah hypotenuse
oh !! yea
actually, diyadia, tan (30) is \[\sqrt{3}/\] so taking the tangent would still give a wrong answer.
no its 1/sqr 3
Tan 30 = 1/sqrt3
bt i have made a mistake i haven't taken square of 5 here so..i'm got wrong ans..
yea, i realized that I just it got messed up. You're right, it is 1/sqrt{3}
bt ans is x=sqr 100 =10 u r right...@ diyadiya
The equation editor and I are still learning to get along...
Lol :)
:)
ok so is the answer x:10 ?
yea any doubt ...
Yep, the answer is 10. Do you understand how we got there?
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