Find the zeros of the function algebraically. f(x) = √8x + 7
ans would be f(0)=7 right ?
That would just give y intercept
so what would be more ....can u explain....
Ok. So you solve the equation in terms of X. \[\sqrt{8}x = -7\]
Then divide both sides by the square root of 8
\[x = -7/\sqrt{8} = -2.474873\]
your answer depends on whether your question is:\[1) f(x)=\sqrt{8x}+7\]or:\[2) f(x)=\sqrt{8}x+7\]i..e is 'x' inside the square root symbol or not?
yea ....bt i have taken it 2nd one...as u written
@amitlpu91 - you have found f(0) rather than (what I believe the question is asking) - find the value for 'x' that makes f(x) = 0
@mlhuyck - can you please clarify whether your question is in form of (1) or (2) above?
bt in this case whatever value plug in for x we can't get f(x)=0 right ...
if the question is of the form (s) above, then @sinusoidal has solved it correctly.
*(2)
watever bt idea is jst like same ......
f(0) is NOT the same as f(x)=0
yea i know...
Evaluating the fuction with x = 0 gives the y intercept
f(0) means that here x=o right...
I believe the equation is of the form (2) above, so @sinusoidal has given the correct solution.
Yes. x = 0 is a y intercept.
y = 0 is an x intercept.
For the graph to intercept the x axis, y must equal zero.
also u can write as f(x)=y .....& hence proceed
you just wrote y = y basically
y and f(x) are both generally the dependent variable.
no it can be considered as f(x)=y so that we can directly plug in value of x and y =0 respectively....got it
as given above equation...
so bcam as f(x) = y =sqr 8x +7 now it is in simplified form ...got it
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