Question

2^x+1 = 64

find x? and how you got the answer

Answer 1

(x-1)² = 64
x-1 = √64
= ± 8
x = 1 ± 8
x = -7, 9

Answer 2

is your question\[2^{x+1}=64\]or\[2^x+1=64\]???

Answer 3

@Kdwndr
please read the question more carefully, you seem not to have understood the problem.

Answer 4

\[For, 2^{x}+1=64\]

\[\rightarrow2^{x}=64-1\]
\[\rightarrow \log 2^{x}=\log 63\]
\[\rightarrow xlog2=\log63\]
\[\rightarrow x= (\log 63)/(\log2)\]

Answer 5

64 equal 2 on exponent 6
so than x+1=6
x=5