Ask your own question, for FREE!
Mathematics 17 Online
OpenStudy (anonymous):

log2^16 + log2^4=?

OpenStudy (diyadiya):

Is it \[\log_{2} 16+\log_{2}4= \]

OpenStudy (anonymous):

i dont get the ideaof ur answer

OpenStudy (diyadiya):

\[\log_{2} 16+\log_{2}4=\] is this your question ?

OpenStudy (anonymous):

log2(16)+log2(4) =6

OpenStudy (anonymous):

log2^(4) = 4log2 log2^16 = 16log2 therefore it would be 16log2+4log2 u can simplify it further

OpenStudy (anonymous):

log_2(16) + log_2(4) = Log_2(16)(4) = Log_2(16)(4) = 6

OpenStudy (anonymous):

i do think the asker meant log2^16+log2^4 that is according to law of logarithms 16log2+4log2

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!