Question

determine the pressure at the bottom of a column of mercury 70 cm high
( density of mercury = 13.6 g/cm^3 )
i want the final result in pascal please

Answer 1

Use the formula I gave you on your last question.

Answer 2

ok
but its cm i want it in pascal

Answer 3

So convert everything to SI units:

distance in meters
g in m/s^2
density is kg/m^3

Answer 4

can you tell me the final result please
i solve it

Answer 5

Pressure = (Force)/(unit Area)
= N / m^2
= kg.m/s^2 / m^2
= kg / (m.s^2)

Now for
h = height in meters
rho = density in kg/m^3
g = acceleration in m/s^2,

the

P = rho.g.h
= kg/m^3 . m/s^2 . m
= kg / (m.s^2)

So that all works.

Hence _your_ job, is convert
- h = height, into meters
- rho = density, into kg/m^3

and then apply the formula for P, P = rho.gh

Answer 6

And 1 Pascal = 1 Pa = 1 kg/(m.s^2). So these are the correct units.

Answer 7

thank you