Which of the following are solutions to the quadratic equation below? Check all that apply. x^2 - 4x + 4 = 3
a. square root 2+3
b. square root 2-3
c. square root 3+2
d. 6
e. negavtive square root 3 +2
f. 2

Question

anonymous · Answer

First you want to make sure that the other side of the equation is 0.
This would become: $$x ^{2} -4x + 1 = 0.$$
You can't simply factor this, so you would have to use the quadratic formula.

anonymous · Answer

$$-b \pm \sqrt{b^2 - 4ac} \over 2a $$

anonymous · Answer

A quadratic equation is $$ax^2 + bx + c$$, so you would plug in the corresponding numbers to the corresponding places.

anonymous · Answer

$$(-4)^2 \pm \sqrt{(-4)^2 - (-4)(1)(1)} \over 2(1)$$