if a < b and c
then nothing, there is no relation...
if a<b and b<c then a<c would be a reasonable observation.
b=d a+c<b+d a+c>b+d b-a=d-c which one is it
those are the choices^ ?
yes
let a=1, b=2, c=3, and d=4 that will reveal the answer.
ans is a+c< b+d
choice 3
...better yet, prove it for the general case by letting a=a b=a+x c=c d=c+y where x,y>0 that shows that the third choice is correct for all numbers: a+c<a+c+x+y
yea....any doubt ...abt this ?
@amitplu91 Please try not to give the answer straight out like that, we want to teach here by making people think, not give answers away. Thanks.
jst look above relation....as a<b & c<d so...a+c < b +d .........
did you ignore my comment amitlpu ? I asked you a favor...
this is not a big pro ..as u acting ........jst try 4 all option & checkit ...u found same like that .....tats it.
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