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Mathematics 11 Online
OpenStudy (anonymous):

if a < b and c

OpenStudy (turingtest):

then nothing, there is no relation...

OpenStudy (turingtest):

if a<b and b<c then a<c would be a reasonable observation.

OpenStudy (anonymous):

b=d a+c<b+d a+c>b+d b-a=d-c which one is it

OpenStudy (turingtest):

those are the choices^ ?

OpenStudy (anonymous):

yes

OpenStudy (turingtest):

let a=1, b=2, c=3, and d=4 that will reveal the answer.

OpenStudy (anonymous):

ans is a+c< b+d

OpenStudy (anonymous):

choice 3

OpenStudy (turingtest):

...better yet, prove it for the general case by letting a=a b=a+x c=c d=c+y where x,y>0 that shows that the third choice is correct for all numbers: a+c<a+c+x+y

OpenStudy (anonymous):

yea....any doubt ...abt this ?

OpenStudy (turingtest):

@amitplu91 Please try not to give the answer straight out like that, we want to teach here by making people think, not give answers away. Thanks.

OpenStudy (anonymous):

jst look above relation....as a<b & c<d so...a+c < b +d .........

OpenStudy (turingtest):

did you ignore my comment amitlpu ? I asked you a favor...

OpenStudy (anonymous):

this is not a big pro ..as u acting ........jst try 4 all option & checkit ...u found same like that .....tats it.

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