A baseball is hit so that it travels straight upward after being struck by the bat. A fan observes that it takes 2.90 s for the ball to reach its maximum height. a) Find the ball's initial velocity. (b) Find the height it reaches
If the ball has initial velocity u and is subject only to the force of gravity, what is the equation for the velocity v at time t? v = (something involving u, g and t) ... what is this expression?
If you're really, really stuck, go back to first principles and definitions. Acceleration is by definition the change of velocity with respect to time. Here the velocity changes from u --> v over time t, and you know it is decelerating at a rate of -g. Therefore \[ Acceleration = \frac{change \ in \ velocity}{change \ in \ time} = \frac{v - u}{t} = -g \] Hence \[ v - u = -gt \] and \[ v = u - gt \] Now, that being the case, for what value of t is v = 0?
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