Question

I have another algebra question. Could you help me with this one ? I don't want the answer but the steps to solve it. I'm stuck at this step (if it is good): (2x-6)/3 = x

Here is the question:

2y = 3x + 2
4x = 5z + 3
y = z - 2

Thank you very much!

Answer 1

it is late, but you have
\[y=\frac{3x+2}{2}=z-2\]
so you have x in term of z as
\[z=\frac{3}{2}x+3\]

Answer 2

then you could replace that here
\[4x = 5z + 3\]and solve for x that way. maybe there is a simpler method

Answer 3

i just checked the correct answer and it does not come from
\[\frac{2x-6}{3}=x\]
which gives
\[x=-6\]
that is not the answer to the problem

Answer 4

Alright I'll investigate a bit more and come back. Thank you very much! :)