So would the derivative of y=Arcsin(3x/4) be [3/\sqrt{16-9x^2}\]?

Question

So would the derivative of y=Arcsin(3x/4) be  [3/\sqrt{16-9x^2}\]?

anonymous · Answer

Just a quick note, you need to put a \ in front of the [ at the beginning for it to register as an equation.

As for your question, your answer is correct. Good job!

anonymous · Answer

Thanks for the tip.

anonymous · Answer

Also, another handy notation to use is \frac{x}{y}, which registers as a fraction with whatever you type into x as the numerator and y as the denominator, so writing \frac{3}{\sqrt{16-9x^2}} will be seen as $$\frac{3}{\sqrt{16-9x^2}}$$ This just makes some fractions easier to read than just using x/y for instance.

anonymous · Answer

ok great