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Mathematics 18 Online
OpenStudy (anonymous):

Help with the mean value theorem https://docs.google.com/viewer?a=v&q=cache:I5OPJb0Q_ugJ:www.sd84.k12.id.us/shs/departments/Math/Search/Calculus/expl5-5a%2520meanvalth.pdf+&hl=en&gl=us&pid=bl&srcid=ADGEESgH1Cz6DLBouaBtF8rObDqCh3aG8o49TeXx5gSOa18XUKm3HTLekNEjI2TwoPFiqnH11MgwjiLruBAGRsh-hBJvF3GHfHRUtdAr39ii_wy2Pi2nAXtda3334Xem8hgzHPacYJrf&sig=AHIEtbT4PsvTDdhjAMtR6M8xmT38ZvSKeQ

OpenStudy (anonymous):

click on the link

OpenStudy (anonymous):

what do you want to know..there are a lot of graph mean value theorem is not applicable in all...just ask a perticular question...

OpenStudy (anonymous):

where it asks me to to draw the secant line and tangent line and from the graph c is approximately what

OpenStudy (anonymous):

okay...if the function is diffreciable in an intervel [a,b]... there must be apoint c on the graph at that point tangent to the curve is parellel to secant joining point a and b... you got me???

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

so what is the slope of secant ???... its [f(b)-f(a)]/(b-a) and slope of tangent at point c??? f'(c) so f'(c) = [f(b)-f(a)]/(b-a) thats the mean value theorem..

OpenStudy (anonymous):

so on the first problem how and hwere will i draw the secant and tangent if u could grpah it forme here

OpenStudy (anonymous):

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