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Find the equation in standard form which passes through (–2, –7) and (1, –1). You must show all work.
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\[m=\left( y _{2}-y _{1} \right)\div \left( x _{2}-x _{1} \right)\]=2 y=mx+c (assuming you're asking for a straight line) so y=2x+c subbing in the point (1,-1) gives c=-3 so y=2x-3
Thanxx
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