Question

Solve the following equation:
4-e^x = 3e^(x+2) with the answer ln(4/(3e^(2) - 1).

Answer 1

e^(x+2) = e^2.e^x

Now use that to find an expression

e^x = something.

Then take the log of both sides.

Answer 2

Making sense?

Answer 3

(and btw, I think there's a sign wrong in your answer.)

Answer 4

I get the concept, but I can't get it to work...

Answer 5

4-e^x = 3e^(x+2)
4 - e^x = 3.e^2.e^x
4 = 3e^2.e^x + e^x
(3e^2 + 1)e^x = 4
e^x = 4/(3e^2 +1)

Answer 6

Ah, fantastic - I got to the second step but couldn't see what to do next! Obvious now, of course... Thank you!