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Mathematics
OpenStudy (anonymous):

if 3+2i is a solution for x^2+mx+n=0, where m and n are real numbers, what is the value of m ?

OpenStudy (anonymous):

I think you would use synthetic division here lemme check.

OpenStudy (anonymous):

I dunno sorry

OpenStudy (anonymous):

thanks though

OpenStudy (phi):

if 3+2i is a solution for x^2+mx+n=0, then 3-2i is also a solution (complex roots come in complex conjugate pairs for quadratic with real coefficients) this means (x - (3+2i))(x+ (3-2i)) gives you the original quadratic.

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