Question

if 3+2i is a solution for x^2+mx+n=0, where m and n are real numbers, what is the value of m ?

Answer 1

I think you would use synthetic division here lemme check.

Answer 2

I dunno sorry

Answer 3

thanks though

Answer 4

if 3+2i is a solution for x^2+mx+n=0,
then 3-2i is also a solution (complex roots come in complex conjugate pairs for quadratic with real coefficients)
this means (x - (3+2i))(x+ (3-2i)) gives you the original quadratic.

Answer 5

http://answers.yahoo.com/question/index?qid=20090512051216AABmJz9