Question

dx/dt of ln((t^2)+3)

Answer 1

\[(\ln(t^2+3))'=\frac{(t^2+3)'}{t^2+3}\]

Answer 2

how about if we dash it again?
what would the answer be?

Answer 3

use product rule.

Answer 4

eerrrr quotient rule i mean

Answer 5

you mean chain rule

Answer 6

could you show me how to do that please?

Answer 7

i showed you above
all you need to do is find the derivative of t^2 and derivative of 3
\[\frac{(t^2+3)'}{t^2+3}=\frac{2t+0}{t^2+3}\]

Answer 8

oh no what i mean
is if we had to dash it again , like second derivative

Answer 9

dash it again?
so you want to find
\[(\frac{2t}{t^2+3})'?\]

Answer 10

you will use quotient rule

Answer 11

yes

Answer 12

derivative ln(t2+3) 1/(t^2+3)*(2t)Dt

Answer 13

dash again