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OpenStudy (anonymous):
Is that \[.00001=\frac{1}{10} (3x+2)\]?
OpenStudy (anonymous):
i think it might be an exponent
OpenStudy (anonymous):
1/10 ^ 3x+2
OpenStudy (anonymous):
\[.00001=\frac{1}{10}^{3x+2}\]\[.00001=\frac{1^{3x+2}}{10^{3x+2}}\]\[.00001=\frac{1}{10^{3x+2}}\]\[0=\frac{100000}{10^{3x+2}}\]\[10^{3x+2}=100000\]\[10^{3x+2}=10^5\] So \[3x+2=5\]\[3x=3\]\[x=1\]
OpenStudy (anonymous):
thanks you really helped me out
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OpenStudy (anonymous):
No worries :)
OpenStudy (anonymous):
.00001 = (1 / 10)^(3x +2)
Multiply and divide by 100000 on left hand side
1/100000 = 1/10^(3x+2)
100000 = 10^(3x + 2)
10^5 = 10^(3x +2)
here base values are equal, so equate the exponents
5 = 3x +2
-2 -2
------------------
3 = 3x
divide by 3 on both sides
3/3 = 3x/3
1 = x