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Mathematics 23 Online
OpenStudy (anonymous):

how do you simplify squaring square roots?

OpenStudy (anonymous):

it depends

OpenStudy (turingtest):

um... like\[(\sqrt{x})^2\]?? Example please

OpenStudy (anonymous):

well the first number is \[\sqrt{?}\]14

OpenStudy (anonymous):

replace the ? with 14

OpenStudy (anonymous):

the square root of 14 is 3.7. so no you cannot because it is a decimal

OpenStudy (anonymous):

so what would you put down as your answer

OpenStudy (anonymous):

for that specific question i would put no. but it would work for instance, the squareroot of 16, which is 4, and the squareroot of 4 is 2. it varies from which number you are finding the square root for

OpenStudy (turingtest):

In general you should try to factor the number under the root sign. \[\sqrt{14}=\sqrt{7\times 2}\]so this cannot be simplified. If however you had\[\sqrt{16}=\sqrt{2\times2\times2\times2}\]you can 'pull out' one copy of any number you have two copies of. In this case we have four 2's, so we can pull two 2's out of the sign and multiply them together:\[\sqrt{16}=\sqrt{2\times2\times2\times2}=2\times2=4\]A couple more examples for the sake of clarity:\[\sqrt{8}=\sqrt{2\times2\times2}=2\sqrt2\]\[\sqrt{108}=\sqrt{2\times2\times3\times3\times3}=(2\times3)\sqrt3=6\sqrt3\]

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