Question

find the equation of the tangent line to y=x^2+3x from point 0,-1
show your work

Answer 1

what y'?

Answer 2

the slope of the tangent line is equal to the derivative of "y"

Answer 3

once we know the slope, the rest is natural

Answer 4

that's all

Answer 5

there's nothing more

Answer 6

then we should find the derivative of y.

Answer 7

how do you do that?

Answer 8

could you teach me how?

Answer 9

practice makes perfect; the question suggests that you should be familiar with the derivative in some way; i can go thru some simple shortcuts for you

Answer 10

but to teach you derivatives is beyond the scope of this environment

Answer 11

alright

Answer 12

y=x^2+3x

the derivative of a sum is the sum of the derivatives

y' = x^2' + 3x'

Answer 13

the derivative of x^n = nx^{n-1} for example:

x^5 = 5x^4

Answer 14

from this, what would you deduce is the derivative of x^2?

Answer 15

what you just explained made no sense to me

Answer 16

but don't worry about it

Answer 17

im not at the level math u r

Answer 18

you taking calculus yet?

Answer 19

nope

Answer 20

thats where you learn about derivatives :)

Answer 21

:)

Answer 22

at any rate; if you knew the derivative got us to 2x+3; this would tell us the equation of the slope at any given point on our line

Answer 23

at x=0 this slope = 3

Answer 24

given a slope and a point we can construct a line:

y = mx -mPx + Py

y = 3x -3(0) +-1

y = 3x -1 looks to be it

Answer 25

good luck with it :)

Answer 26

ok, thanks