Question

find f`(x) for sqroot (x^(2)+4) some how i got x which i believe to be the wrong answer

Answer 1

\[\sqrt{x ^{2}+4}\] here is what it looks like

Answer 2

\[f'(x)=2x/(2(x^2+4))\]

Answer 3

sqrt = ^1/2

Answer 4

oh thats right

Answer 5

so it would be x^2/2?

Answer 6

\[(x^2+4)^{1/2}\]
\[\frac{1}{2}(x^2+4)^{1/2-2/2}*(x^2+4)'\]
\[\frac{1}{2}(x^2+4)^{1/2-2/2}*2x\]

Answer 7

thank you both

Answer 8

forgot to actually do the 1/2 - 2/2 lol

Answer 9

\[\frac{1}{2}(x^2+4)^{1/2-2/2}*2x\]
\[\frac{2}{2}x(x^2+4)^{-1/2}\]
\[x(x^2+4)^{-1/2}=\frac{x}{\sqrt{x^2+4}}\]

Answer 10

well i got x because i have horrible algebra skills :D

Answer 11

so who know that these could be done a on the calculator