Let f(x)=x^3−2x. Calculate the difference quotient f(2+h)−f(2)/h for

h=.1
h=.01
h=−.01
h=−.1

if you can demonstrate how to do one, I will learn to do the rest

Question

Let f(x)=x^3−2x. Calculate the difference quotient f(2+h)−f(2)/h for

h=.1
h=.01
h=−.01
h=−.1

if you can demonstrate how to do one, I will learn to do the rest

lalaly · Answer

$$f(2+h)=(2+h)^3-2(2+h)$$$$f(2)=2^3-2(2) =8-4=4$$so the first one h=0.1$$f(2+0.1)-\frac{f(2)}{0.1}$$$$=(2+0.1)^3-2(2+0.1)-\frac{4}{0.1}$$and simplify

anonymous · Answer

thanks

anonymous · Answer

The slope of the tangent line to the graph of f(x) at x=2 is m=limh→0 f(2+h)−f(2)/h= ???