Question

How would you integrate pi(16sin^2(x)) dx?

Answer 1

Use \(\sin^2(x)=\large\frac{1- \cos(2x)}{2}\).

Answer 2

Can I pull out the 16pi?

Answer 3

Yes.

Answer 4

Okay I did and I got 4pi^2..is that right?

Answer 5

oh..end points are 0-pi/2

Answer 6

0 to pi/2..sorry!

Answer 7

Correct!

Answer 8

Thank you very much!! :))

Answer 9

Glad to help.