Question

Drawing: Solve for x

Answer 1

Use \(\Large SohCahToa\) to solve.

Answer 2

WHY AM I DOING SUCH STUPID MISTAKES TODAY

Answer 3

today is not my math day, i literally forgot how to use Sohcahtoa.

Answer 4

Did you remember?
\[\Large \begin{array}{l}
\sin \theta = \frac{o}{h}\\
\cos \theta = \frac{a}{h}\\
\tan \theta = \frac{o}{a}
\end{array}\]So in this question, we have the hypotenuse, and x is either opposite 68 or adjacent to 22; so we can use sine or cosine to find the unknown.

\[\Large \begin{array}{l}
\sin \theta = \frac{o}{h}\\
\sin 68 = \frac{x}{{6.6}}\\
x = \sin 68 \cdot 6.6 = 6.12\\
\cos \theta = \frac{a}{h}\\
\cos 22 = \frac{x}{{6.6}}\\
x = \cos 22 \cdot 6.6 = 6.12
\end{array}\]
Since it's a right triangle (we know this since 180 - 68 - 22 = 90), we can work out the other unknown using Pythagoras' theorem, or just using the same rules as above.